Corey White
2016-07-07 17:26:57 UTC
The system of Kabbalah I created maps numbers to words. I'm trying to prove that numbers are basically just variables, and any problem can have more than one answer. I'm sure its true, but the education system doesn't want people to know this.
My problem was assigning numbers to the words we normally use instead of the numeric symbols 1 through 10. To do this each letter is given one unique number. The numerical values for all the letters in a word are added together. So o+n+e=1, and t+w+o=2. That's all there is too it! For consistency and completeness all of the letters have one unique number.
This didn't require the entire alphabet. In fact only 16 letters are needed to make any number. Here is a chart with the solution:.
E = -2
F = -6
G = 0
H = -7
I = 7
L = 9
N = 2
O = 1
R = 4
S = 3
T = 10
U = 5
V = 6
W = -9
X = -4
Z = -3
Here are the first 11 numbers spelled out with this:
(zero) = (-3 + -2 + 4 + 1)
(one) = (1 + 2 + -2)
(two) = (10 + -9 + 1)
(three) = (10 + -7 + 4 + -2 + -2)
(four) = (-6 + 1 + 5 + 4)
(five) = (-6 + 7 + 6 + -2)
(six) = (3 + 7 + -4)
(seven) = (3 + -2 + 6 + -2 + 2)
(eight) = (-2 + 7 + 0 + -7 + 10)
(nine) = (2 + 7 + 1 + -2)
(ten) = (10 + -2 + 2)
To contemplate larger numbers you use exponents.
ten^two = (10 + -2 + 2)^(10 + -9 +2)
ten^two = (10)^(2)
ten^two = 100
Here is a more complicated answer:
(ten^(two))*three = (10 + -2 + 2)^(10 + -9 + 1) * (10 + -7 + 4 + -2 + -2)
(ten^(two))*three = ( 10^2 ) * 3
(ten^(two))*three = ( 100 ) * 3
(ten^(two))*three = 300
My problem was assigning numbers to the words we normally use instead of the numeric symbols 1 through 10. To do this each letter is given one unique number. The numerical values for all the letters in a word are added together. So o+n+e=1, and t+w+o=2. That's all there is too it! For consistency and completeness all of the letters have one unique number.
This didn't require the entire alphabet. In fact only 16 letters are needed to make any number. Here is a chart with the solution:.
E = -2
F = -6
G = 0
H = -7
I = 7
L = 9
N = 2
O = 1
R = 4
S = 3
T = 10
U = 5
V = 6
W = -9
X = -4
Z = -3
Here are the first 11 numbers spelled out with this:
(zero) = (-3 + -2 + 4 + 1)
(one) = (1 + 2 + -2)
(two) = (10 + -9 + 1)
(three) = (10 + -7 + 4 + -2 + -2)
(four) = (-6 + 1 + 5 + 4)
(five) = (-6 + 7 + 6 + -2)
(six) = (3 + 7 + -4)
(seven) = (3 + -2 + 6 + -2 + 2)
(eight) = (-2 + 7 + 0 + -7 + 10)
(nine) = (2 + 7 + 1 + -2)
(ten) = (10 + -2 + 2)
To contemplate larger numbers you use exponents.
ten^two = (10 + -2 + 2)^(10 + -9 +2)
ten^two = (10)^(2)
ten^two = 100
Here is a more complicated answer:
(ten^(two))*three = (10 + -2 + 2)^(10 + -9 + 1) * (10 + -7 + 4 + -2 + -2)
(ten^(two))*three = ( 10^2 ) * 3
(ten^(two))*three = ( 100 ) * 3
(ten^(two))*three = 300